Question

A 750 kg car traveling 22.0 m/s due north crashes into a 1500 kg truck traveling 20 m/s due west. The two vehicles become locked together and travel 19.0 m before stopping. Find the average frictional force (magnitude and direction) that brings the two to a stop.

Answer 1

p1=m1•v1
p2=m2•v2
p12=sqrt(p1²+p2²)

v= p12/(m1+m2) = sqrt(p1²+p2²)/(m1+m2)

mv²/2 =F(fr) •s
F(fr) = mv²/2•s

Answer 2

32233

Answer 3

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