Asked by Anonymous
Calculate the final temperature of 215 mL of water initially at 40 ∘C upon absorption of 16 kJ of heat.
Answers
Answered by
DrBob222
Assuming the density of H2O is 1 g/mL
q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
16,000 = 215 x 4.184 x (Tfinal-40)
q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
16,000 = 215 x 4.184 x (Tfinal-40)
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