Asked by Brittany

Calculate the final temperature of a mixture of 200.0g of ice initially at -16.5 Celsius and 406.0g of water initially at 84.5 degrees Celsius.
Answered by DrBob222
q1 = heat to raise temperature of ice from -16.5 C to zero C.
q1 = mass ice x specific heat ice x (Tfinal-Tinitial)

q2 = heat to melt the ice.
q2 = mass melted ice x heat fusion

q3 = heat to raise temperature of melted ice from zero C to final T.
q3 = mass melted ice x specific heat water x (Tfinal-Tinitial)

q4 = heat released by warm water at 84.5 C when lowered to final T.
q4 = mass warm water x specific heat H2O x (Tfinal-Tinitial)

Substitute for each of the above and set to zero as
q1 + q2 + q3 = 0
and solve for Tfinal.
Post your work if you get stuck.
Answered by Anonymous
thank you
Answered by Anonymous
what about q4
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