Asked by Anonymous

Calculate the final temperature of 283 mL of water initially at 30 degrees celcius upon absorption of 19 kJ of heat
Answered by DrBob222
q = mass water x specific heat water x (Tfinal-Tinitial)
19,000 = 283 x 4.184 x (Tf - 30)
Solve for Tfinal.
Answered by Anonymous
31.6
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