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Find the equation of the line parallel to the line joining (-3,-1) and (4,-3) and having y-intercept 2.

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Given: A(-3, -1), B(4, -3), Y-int. = 2.

Y = mx + b.
m = (-3-(-1))/(4-(-3)) = -2/7.

-1 = (-2/7)(-3) + b.
b = -13/7.

Eq: Y = (-2/7)x - 13/7.
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