Asked by Sydney
Find an equation of the line that passes through the point
(−7, −8), and is perpendicular to the line 7x + 4y + 8 = 0.
(−7, −8), and is perpendicular to the line 7x + 4y + 8 = 0.
Answers
Answered by
Reiny
If perpendicular to 7x + 4y + 8 = 0, then its equation must be 4x - 7y + c = 0
with (-7,-8) on it, -28 +56 + c = 0
c = -28
new equation: 4x - 7y - 28 = 0
with (-7,-8) on it, -28 +56 + c = 0
c = -28
new equation: 4x - 7y - 28 = 0
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