Asked by Anonymous
Find the equation of the line that passes through (−3, 2) and the intersection of the lines x+2y=0 and 3x+y+5=0.
For the intersection, I got (-2,1) and for the equation i got y=x+3. but apparently those aren't the answer. Could you provide a way to solve, but not the complete anser for the question, but i might ask for one after i have tried the suggestion
For the intersection, I got (-2,1) and for the equation i got y=x+3. but apparently those aren't the answer. Could you provide a way to solve, but not the complete anser for the question, but i might ask for one after i have tried the suggestion
Answers
Answered by
bobpursley
ok, you have the intersection (-2,1)
now the line
slope=(changeY)/(changex)=(1-2)/(-2+3)=-1
y= mx+b
1= (-1)(-2)+b
b=1-2=-1
y=-x-1 check that.
now the line
slope=(changeY)/(changex)=(1-2)/(-2+3)=-1
y= mx+b
1= (-1)(-2)+b
b=1-2=-1
y=-x-1 check that.
Answered by
Anonymous
it worked thanks for the help
Answered by
Steve
you have a point and a slope, so use the point-slope form of the line:
y-2 = -1(x+3)
y-2 = -1(x+3)
Answered by
Anonymous
Thank you for that suggestion!!
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