Asked by Anonymous
                Find the equation of the line that passes through (−3, 2) and the intersection of the lines x+2y=0 and 3x+y+5=0.
For the intersection, I got (-2,1) and for the equation i got y=x+3. but apparently those aren't the answer. Could you provide a way to solve, but not the complete anser for the question, but i might ask for one after i have tried the suggestion
            
        For the intersection, I got (-2,1) and for the equation i got y=x+3. but apparently those aren't the answer. Could you provide a way to solve, but not the complete anser for the question, but i might ask for one after i have tried the suggestion
Answers
                    Answered by
            bobpursley
            
    ok, you have the intersection (-2,1)
now the line
slope=(changeY)/(changex)=(1-2)/(-2+3)=-1
y= mx+b
1= (-1)(-2)+b
b=1-2=-1
y=-x-1 check that.
    
now the line
slope=(changeY)/(changex)=(1-2)/(-2+3)=-1
y= mx+b
1= (-1)(-2)+b
b=1-2=-1
y=-x-1 check that.
                    Answered by
            Anonymous
            
    it worked thanks for the help
    
                    Answered by
            Steve
            
    you have a point and a slope, so use the point-slope form of the line:
y-2 = -1(x+3)
    
y-2 = -1(x+3)
                    Answered by
            Anonymous
            
    Thank you for that suggestion!!
    
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