Question

Find the equation of the line that passes through (−3, 2) and the intersection of the lines x+2y=0 and 3x+y+5=0.

For the intersection, I got (-2,1) and for the equation i got y=x+3. but apparently those aren't the answer. Could you provide a way to solve, but not the complete anser for the question, but i might ask for one after i have tried the suggestion

Answer 1

ok, you have the intersection (-2,1)

now the line
slope=(changeY)/(changex)=(1-2)/(-2+3)=-1
y= mx+b
1= (-1)(-2)+b
b=1-2=-1
y=-x-1 check that.

Answer 2

it worked thanks for the help

Answer 3

you have a point and a slope, so use the point-slope form of the line:

y-2 = -1(x+3)

Answer 4

Thank you for that suggestion!!