Asked by Ande2
If y=2xCos2x-Sin2x, find dy/dx when x=π/2.
Answers
Answered by
oobleck
Just use the product rule and chain rule
y=2x Cos2x-Sin2x
y' = 2cos2x - 2xsin2x*2 - 2cos2x
= -4x sin2x
y=2x Cos2x-Sin2x
y' = 2cos2x - 2xsin2x*2 - 2cos2x
= -4x sin2x
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