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A water balloon is fired at 34.0 m/s from a water cannon, which is aimed at an angle of 18° above the ground. The center of the...Asked by anonymous
A water balloon is fired at 34.0 m/s from a water cannon, which is aimed at an angle of 18° above the ground. The center of the cannon's target (which has a radius of 1.0 m) is painted on the asphalt 42.0 m away from the water cannon.
will the balloon hit the target? Can someone show me how to do it please?
will the balloon hit the target? Can someone show me how to do it please?
Answers
Answered by
oobleck
Recall that the range of a missile is given by
R = (v^2 sin2θ)/g
plug in your numbers and see whether 41.0 <= R <= 43.0
so, what do you get for R?
R = (v^2 sin2θ)/g
plug in your numbers and see whether 41.0 <= R <= 43.0
so, what do you get for R?
Answered by
MONJAMA Musa
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