Asked by rakesh
What volume of 0.140 M HCl is needed to neutralize 2.93 g of Mg(OH)2
Answers
Answered by
DrBob222
Mg(OH)2 + 2 HCl ==> MgCl2 + 2H2O
mols Mg(OH)2 = grams/molar mass = ?
mols HCl = twice that (from the coefficients in the balanced equation.
Then molarity HCl = mols HCl/L HCl.. You know molarity and mols, solve for L. Convert to mL if needed.
mols Mg(OH)2 = grams/molar mass = ?
mols HCl = twice that (from the coefficients in the balanced equation.
Then molarity HCl = mols HCl/L HCl.. You know molarity and mols, solve for L. Convert to mL if needed.
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