Question

A 2.50-kg object is moving along the x -axis at 1.60 m/s. As it S S passes the origin, two forces F 1 and F 2 are applied, both in the y -direction (plus or minus). The forces are applied for 3.00 s, after S which the object is at x S = 4.80 m, y = 10.8 m. If F 1 = 15.0 N, what’s F 2 ?

Answer 1

determine the net y force.
10.8m=a*t=(netforcey/mass)*time
solve fodr netforceinY direction
then, F2=NetforceinY - F1

Answer 2

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