Asked by Anonymous
Consider a particle moving along the x-axis where
x(t)
is the position of the particle at time t,
x' (t)
is its velocity, and
x'' (t)
is its acceleration.
x(t) = t3 − 12t2 + 21t − 9, 0 ≤ t ≤ 10
Find the open t-intervals on which the particle is moving to the right. (Enter your answer using interval notation.)
x(t)
is the position of the particle at time t,
x' (t)
is its velocity, and
x'' (t)
is its acceleration.
x(t) = t3 − 12t2 + 21t − 9, 0 ≤ t ≤ 10
Find the open t-intervals on which the particle is moving to the right. (Enter your answer using interval notation.)
Answers
Answered by
oobleck
moving to the right means x is increasing.
So, where do you have x'(t) > 0?
So, where do you have x'(t) > 0?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.