moving to the right means x is increasing.
So, where do you have x'(t) > 0?
Consider a particle moving along the x-axis where
x(t)
is the position of the particle at time t,
x' (t)
is its velocity, and
x'' (t)
is its acceleration.
x(t) = t3 − 12t2 + 21t − 9, 0 ≤ t ≤ 10
Find the open t-intervals on which the particle is moving to the right. (Enter your answer using interval notation.)
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