Asked by naomi
a 2 kg object moving at 5 m/s enters a surface with the coefficient of kinetic friction is .1 and is brought to a full stop. If the cart moved 12.8 m calculate:
a) the net work done on the object over the 12.8 m distance (I got 6.4j, but it's probably wrong)
b) change in kinetic energy of the object
c) in what form of energe was the kinetic energy changed?
a) the net work done on the object over the 12.8 m distance (I got 6.4j, but it's probably wrong)
b) change in kinetic energy of the object
c) in what form of energe was the kinetic energy changed?
Answers
Answered by
bobpursley
Net work=mu*m*g*distance
change KE=KEinitial-KEfinal=KEinitial-0
friction results in heat.
change KE=KEinitial-KEfinal=KEinitial-0
friction results in heat.
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