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a 2 kg object moving at 5 m/s enters a surface with the coefficient of kinetic friction is .1 and is brought to a full stop. If the cart moved 12.8 m calculate:

a) the net work done on the object over the 12.8 m distance (I got 6.4j, but it's probably wrong)

b) change in kinetic energy of the object

c) in what form of energe was the kinetic energy changed?
16 years ago

Answers

bobpursley
Net work=mu*m*g*distance

change KE=KEinitial-KEfinal=KEinitial-0

friction results in heat.
16 years ago

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