Asked by Briana
A 1.2 kg object is moving with a speed of 8.0 m/s collides perpendicularly with a wall and emerges with a speed of 6.0m/s in the opposite direction perpendicular to the wall. If the object is in contact with the wall for 2.0m/s. What is the magnitude of the average force on the object by the wall?
Answers
Answered by
StarofDavid
8.4Kn
Answered by
Xian
Could you please explain how you got to your answer?
Answered by
Elena
F=Δp/Δt=mΔv/Δt=
=m[v₂-(-v₁)]/Δt=
=m(v₂+v₁)/Δt=
=1.2•(6+2)/ Δt=…
Check the given data (time of contact!!!!)and substitute it
=m[v₂-(-v₁)]/Δt=
=m(v₂+v₁)/Δt=
=1.2•(6+2)/ Δt=…
Check the given data (time of contact!!!!)and substitute it
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