Question
1) A buffer solution was made by adding 6.56g of sodium ethanoate to 1dm3 of 0.02moldm-3 ethanoic acid.
a) What is the concentration of the sodium ethanoate?
b)What is the concentration of the ethanoic acid?
a) What is the concentration of the sodium ethanoate?
b)What is the concentration of the ethanoic acid?
Answers
CH3COONa = NaAc = base
CH3COOH = HAc = acid
(NaAc) = 0.56 g/molar mass/1L
(HAc) = 0.02 M from the problem. Post your work if you get stuck.
CH3COOH = HAc = acid
(NaAc) = 0.56 g/molar mass/1L
(HAc) = 0.02 M from the problem. Post your work if you get stuck.
Wouldn't the concentration for CH3COONa be:
6.56 g /82 gmol-1 /1.00656 L
6.56 g /82 gmol-1 /1.00656 L
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