Question

what is the ph of a buffer made by mixing 2.00g of sodium acetate with 20.00ml of 1.20 mol/l acetic acid and adding enough water so the final volume of the mixture is 100.0 ml?
(base) = (sodium acetate) = grams/molar mass/0.100 = ?M.
(acid) = (acetic acid) = 1.20M x (20/100) = ?M
pH = pKa + log (base)/(acid)
Substitute and solve for pH. The answer should be about 4.8 or so.

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