Asked by Anonymous
You have made a buffer solution where you added 9 mL 1M Acetic Acid and 0.82 grams Sodium Acetate and diluted it with deionized water to 100 mL. If the Ka for Acetic Acid is 1.76*10-5 and the molecular weight of Sodium Acetate is 82.03 g/mole, what is the pH of the buffer you prepared?
Answers
Answered by
DrBob222
base = NaAc = (grams/molar mass)/L
acid = HAc = 1M x (9/100) = ?
Substitute into the Henderson-Hasselbalch equation and solve for pH.
Post your work if you get stuck.
acid = HAc = 1M x (9/100) = ?
Substitute into the Henderson-Hasselbalch equation and solve for pH.
Post your work if you get stuck.
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