Asked by Alice
For what value of t is the slope of the curve undefined for the graph defined by x = 10 – t^2, y = t^3 – 12t?
Type your answer in the space below to the nearest whole number. (ex: 4)
NOTE: I asked before this question but I didn't get the answer. I don't understand. Can you help me, please? I am sorry to bother you. Thanks in advance
Type your answer in the space below to the nearest whole number. (ex: 4)
NOTE: I asked before this question but I didn't get the answer. I don't understand. Can you help me, please? I am sorry to bother you. Thanks in advance
Answers
Answered by
oobleck
How many times we gonna do this?
x = 10 – t^2, y = t^3 – 12t
dy/dx = (dy/dt)/(dx/dt) = (3t^2-12)/(-2t)
As with all rational functions, the value is undefined when the denominator is zero. Division by zero is not defined.
So, dy/dx is undefined when t=0
https://www.wolframalpha.com/input/?i=plot+x+%3D+10+%E2%80%93+t%5E2,+y+%3D+t%5E3+%E2%80%93+12t+for+0+%3C%3D+t+%3C%3D+1
You can see from the plot that when t=0 the tangent at (10,0) is vertical.
x = 10 – t^2, y = t^3 – 12t
dy/dx = (dy/dt)/(dx/dt) = (3t^2-12)/(-2t)
As with all rational functions, the value is undefined when the denominator is zero. Division by zero is not defined.
So, dy/dx is undefined when t=0
https://www.wolframalpha.com/input/?i=plot+x+%3D+10+%E2%80%93+t%5E2,+y+%3D+t%5E3+%E2%80%93+12t+for+0+%3C%3D+t+%3C%3D+1
You can see from the plot that when t=0 the tangent at (10,0) is vertical.
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