Question
The volume of mixture of 2gms of helium and 7gms of nitrogen under STP conditions of
A) 22.4lit B) 11.2lit
C) 16.8 D) 5.6lit
A) 22.4lit B) 11.2lit
C) 16.8 D) 5.6lit
Answers
Anonymous
2g*(1 mole/4.003g)=0.5 moles of He
7g*(1 mole/14.01g)=0.5 moles of N
Together we have a total of 1 mole of gas.
At STP, 1 mole of a gas has a volume of 22.4L. That is just a relationship that you must commit to memorization.
7g*(1 mole/14.01g)=0.5 moles of N
Together we have a total of 1 mole of gas.
At STP, 1 mole of a gas has a volume of 22.4L. That is just a relationship that you must commit to memorization.
KRISHNA
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