Question

1. What volume will a mixture of 5.00 mol of H2 and 0.500 mol of CO2 occupy at STP?

Answer 1

Use PV = nRT. Substitute 5.5 for n.

Answer 2

Here's my work please tell me if its right DrBob222;
P=760 torr or 1 atm
V=?
T= 273 K
n= 5.00 + 0.500= 5.5 mole

V= nRT/P
= (5.5 mol)(0.0821 L x atm/mol*K)(273 K)
divided by 1 atm
= 123.27 L