Asked by Zilani
The total volume of mixture of 2grams of helium and 7 grams of nitrogen at s.t.p is 1)22.4 2)11.2 3)16.8 4)5.6 in liters help me please.
Answers
Answered by
bobpursley
you have 1/2 mole of He, 1/2 mole of N2, total one mole of gas mixture. At STP, that is 22.4 dm^3. I recommend you memerorize that.
Now if you want to work it out
PV=nRT
V=nRT/P put in STP numbers, N at one mole, and you will get a volume of 0.0223m^3 or 22.4 dm^3 or what folks living in the past century called 22.4 liters. If you wish, your teacher could teach it to you in gallons, or Imperial gallons, or cubic centimeters, or even bushels. 22.4 dm^3
Now if you want to work it out
PV=nRT
V=nRT/P put in STP numbers, N at one mole, and you will get a volume of 0.0223m^3 or 22.4 dm^3 or what folks living in the past century called 22.4 liters. If you wish, your teacher could teach it to you in gallons, or Imperial gallons, or cubic centimeters, or even bushels. 22.4 dm^3
Answered by
Om
Please help. Me in simple language
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