Asked by Linda

Simplify. State the restrictions on the variable.

(6y-30/(y-1)) * (5y-5/3y^2-15y)
Answered by anonymous
there is an app called photomath, it solves the math for you.
(6y-30/(y-1)) * (5y-5/3y^2-15y)
=(6(y-5))/(y-1) * (5(y-1))/(3y(y-5))
=2*(5/y)
=10/y
Answered by Question was not answered - Reiny
There were two divisions, one by (y-1) , so y ≠ 1
the other was (3y(y-5)) , so y ≠ 0, 5

final answer would be
= 10/y , y ≠ 0, 1, 5
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