using the symmetry of the region
A = 2∫[0,2] (4-x)-x dx
Now just plug and chug
check: you have two triangles, each of base 4 and height 2.
Find the área of the región bounded by the graphs of y=x, y=-x+4, and y=0
A) 4
B) 2
C) 8
D) no me of these
4 answers
Could you explain me more, pleaseee
what - the concept of an integral and areas, or just how to evaluate the integral? It's a simple application of the power rule.
Divide the area up into thin strips, each of width dx, and with height the distance between the lines.
∫ (4-x)-x dx = ∫4-2x dx = 4x - x^2
Now evaluate at the limits and subtract.
Still confused? Read your text -- I'm sure it has examples.
Divide the area up into thin strips, each of width dx, and with height the distance between the lines.
∫ (4-x)-x dx = ∫4-2x dx = 4x - x^2
Now evaluate at the limits and subtract.
Still confused? Read your text -- I'm sure it has examples.
Thanks Oobleck
1 answer