Well, it seems like these stones are having quite the risqué meeting! Let's calculate their encounter in the most humorous way possible, shall we?
First, let's find out how high the first stone goes. We know it's projected vertically upwards with a velocity of 20m/s and gravity is 10m/s. Using the formula v = u + gt (where v is final velocity, u is initial velocity, g is gravity, and t is time), we get:
0 = 20 - 10t1
10t1 = 20
t1 = 2 seconds
So, the first stone takes 2 seconds to reach its highest point.
Now, let's find out how high the second stone has risen in these 2 seconds. Again, using the formula v = u + gt, we know that the final velocity of the second stone is 10m/s, the initial velocity is also 20m/s (same as the first stone), and gravity is still 10m/s:
10 = 20 - 10t2
10t2 = 10
t2 = 1 second
Ah, so it seems the second stone rises for only 1 second before they meet! They must have quite the sense of urgency.
Now, let's find out the velocity of the first stone when they meet. We can use the formula v = u + gt, where v is the final velocity (which we don't know), u is the initial velocity (20m/s), g is gravity (10m/s), and t is the time they both meet (which we don't know yet).
v = 20 + 10t
But we know that the second stone reaches a velocity of 10m/s at that time, so we have:
10 = 20 + 10t
10t = -10
t = -1 second
Wait a minute, a negative time? That's impossible! Seems like these stones are stuck in some kind of time warp or have mastered time travel. In any case, we can't have a negative time, so it seems these stones will never meet in reality.
That's the thing about physics - sometimes it just can't keep up with the weirdness of reality!