Asked by ogboye
A stone is projected vertically upward with a speed of 30m/s from the top of a tower of height 50m neglecting air resistance. Determine the maximum height reached from the ground
Answers
Answered by
Damon
Hi = 50
Vi = 30
v = Vi - 9.81 t
at top v = 0
so
t = 30/9.81 = 3.06 seconds to top
h = Hi + Vi t - 4.9 t^2
h = 50 + 30(3.06) - 4.9(3.06)^2
Vi = 30
v = Vi - 9.81 t
at top v = 0
so
t = 30/9.81 = 3.06 seconds to top
h = Hi + Vi t - 4.9 t^2
h = 50 + 30(3.06) - 4.9(3.06)^2
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