Asked by Alina
                The function g is defined by g(x)=9k−4, where k is a constant. Find k, if the graph of g passes through the point (7,−2).
            
            
        Answers
                    Answered by
            Steve
            
    Your function g(x) doesn't have any x's in it! If it's a constant, then
9k-4 = -2
k = 2/9
You sure you don't mean
g(x) = 9kx-4
or
g(x) = 9x-4k or something?
since g(7) = -2, if g(x) = 9kx-4, then
9k*7-4 = -2
63k = 2
k = 2/63
If that's not what you wanted, then fix g(x) and just plug in 7 for x and -2 for g(x) in the equation, then solve for k.
    
9k-4 = -2
k = 2/9
You sure you don't mean
g(x) = 9kx-4
or
g(x) = 9x-4k or something?
since g(7) = -2, if g(x) = 9kx-4, then
9k*7-4 = -2
63k = 2
k = 2/63
If that's not what you wanted, then fix g(x) and just plug in 7 for x and -2 for g(x) in the equation, then solve for k.
                    Answered by
            ur dad
            
    no
    
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