Asked by Rachel
Let f be the function defined by f(x)=x^3 + x. If g(x)= the inverse of f(x), and g(2)=1, what is the value of g'(2)?
Answers
Answered by
Steve
f'(x) = 3x^2+1
g'(2) = 1/f'(g(2)) = 1/f'(1) = 1/4
g'(2) = 1/f'(g(2)) = 1/f'(1) = 1/4
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