Asked by miriam

The perimeter of a rectangle is 66m. if the width were doubled and the length were increased by 24m, the perimeter would be 132m. What are the length and width of the rectangle
Answered by Reiny
original:
length --- x
width ---- y
2x + 2y = 66
x+y = 33
y = 33-x

new rectangle:
length ---- x+24
width = 2y
perimeter= 2(x+24) + 2(2y) = 132
2x + 48 + 4y = 132
2x + 48 + 4(33-x) = 132
-2x + 180 = 132

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Answered by deeze nuts
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