Asked by favour
a geometric progression is given as 8/81-4/27+2/9.find the sum of the first five terms.
Answers
Answered by
Reiny
Check to see that the value of r = 3/2 , that is ...
(-4/27) ÷ (8/81) and (2/9) ÷ (-4/27) = -3/2
so a = 8/81, and r = -3/2
sum(n) = a(1 - r^n)/(1-r)
sub in the values and evaluate, let me know what you got
(-4/27) ÷ (8/81) and (2/9) ÷ (-4/27) = -3/2
so a = 8/81, and r = -3/2
sum(n) = a(1 - r^n)/(1-r)
sub in the values and evaluate, let me know what you got
Answered by
Anonymous
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