Question

A 32.8 kg child rides a 7.00 kg toboggan down a 12.0 m high snowy hill. If the child starts from rest and has a speed of 7.15 m/s at the bottom of the hill, what is the change in thermal energy of the child on their toboggan and the snow?

bobpursley
original PE=mgh=32.8*9.8*12
final KE=1/2 m v^2=.5*32.8*7.15^2
originalPE-finalKE-heatenergylost=0
solve for heatenergylost

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