Asked by Anna
A -A child rides a toboggan down a hill that descends at anangle of21.8◦ to thehorizontal. The hill is 42.6 m long. What is the horizontal component of the child’s displacement? Answer in units of m.
B - What is the vertical component of the child’s displacement? Answer in units of m.
For A I got 39.6 m, however how would I solve B?
B - What is the vertical component of the child’s displacement? Answer in units of m.
For A I got 39.6 m, however how would I solve B?
Answers
Answered by
Henry
A. X = 42.8*Cos21.8 = 39.7 m.
B. Y = 42.8*sin21.8 = 15.9 m.
B. Y = 42.8*sin21.8 = 15.9 m.
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