Question

A -A child rides a toboggan down a hill that descends at anangle of21.8◦ to thehorizontal. The hill is 42.6 m long. What is the horizontal component of the child’s displacement? Answer in units of m.

B - What is the vertical component of the child’s displacement? Answer in units of m.

For A I got 39.6 m, however how would I solve B?
A. X = 42.8*Cos21.8 = 39.7 m.

B. Y = 42.8*sin21.8 = 15.9 m.

Related Questions

A child rides a toboggan down a hill that descends at an angle of 15.5 ◦ to the horizontal. The... A child rides a toboggan down a hill that descends at an angle of 15.5◦ to the horizontal. The hill... A child rides a toboggan down a hill that descends at an angle of 26.6 degrees to the horizontal. Th... A 32.8 kg child rides a 7.00 kg toboggan down a 12.0 m high snowy hill. If the child starts from res...