Question
A 2.9-kg bucket is lifted upward with a force of 46N against the force of gravity. Calculate it’s upward acceleration, ignoring all frictional forces.
Answers
bobpursley
46-mg=ma
46-2.9*9.8=2.8 a
a= (46/2.8 -9.8)=6.63m/s^2 check that
46-2.9*9.8=2.8 a
a= (46/2.8 -9.8)=6.63m/s^2 check that