Asked by shegaw

If air contains 78%N2 by volume ,what is the solubility of nitrogen in water at 25°©?
Answered by bobpursley
<<Henry's law:
[N₂] = kH ∙ p(N₂)

Assuming ideal gas mixture the partial pressure of nitrogen equals 78% of the total pressure, i.e.
p(N₂) = 0.78 atm

So the solubility of nitrogen under these conditions is:
[N₂] = 7×10⁻⁴mol/(Latm) ∙ 0.78 = 5.46×10⁻⁴mol/L >>
Answered by Habtamu
%V is given. How it could be compared as partial pressure?
Answered by Mahider
Thank
Answered by muhidin
10Q
Answered by Aphorius P. Thompson
what happen to the Atm in the problem?
Answered by Kirti
P Thompson atm given in the question is total pressure and with the help of that we have to find partial pressure
Answered by Seid
[email protected]
Answered by AwelMohammed
5.46×10^-4mol/l
Answered by Bethelhem
Is Henry's constant the same at 20°c and 25°c???
Answered by Habtish belete
No the Henry's constant is only at 25 c°
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