Asked by Sarah
An escalator carries 60 people of average mass 70 kg to a height of 5m in one minute.Find the power needed to do this.
Answers
Answered by
Damon
Force * distance /time
= 60 * 70 * 9.81 * 5 / 60 watts
= 60 * 70 * 9.81 * 5 / 60 watts
Answered by
Anonymous
w=m*g
w=(60 people* 70 kg)* 10 (rounded of from 9.81 m/s^2)
w=42000 N
Work=42000 N * 5 m
Work=210 000 J
Power=210 000 J/60 s
Power=3500 W
w=(60 people* 70 kg)* 10 (rounded of from 9.81 m/s^2)
w=42000 N
Work=42000 N * 5 m
Work=210 000 J
Power=210 000 J/60 s
Power=3500 W
Answered by
Aisha
I am not understand how u use 10 rounded
Answered by
Fasih
because 10 is the gravity. w = m*g
g = 10
m = 70*60
t = 60
p = work done/time
work done = F*distance
f = m*g
f = 70*60*10
f = 42000
distance = 5
work done = 42000*5
work done = 210000
p = work done/t
p = 210000/60
p = 3500 watt
g = 10
m = 70*60
t = 60
p = work done/time
work done = F*distance
f = m*g
f = 70*60*10
f = 42000
distance = 5
work done = 42000*5
work done = 210000
p = work done/t
p = 210000/60
p = 3500 watt
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