Asked by Arielle
A certain escalator travels at a rate of 10.6 m/min, and its angle of inclination is 32.5 degrees. What is the vertical component of the velocity? How long will it take a passenger to travel 10.0 m vertically?
Answers
Answered by
Steve
v = 10.6
v<sub>x</sub> = 10.6 cos 32.5
v<sub>y</sub> = 10.6 sin 32.5
Now that you have v<sub>y</sub>, the time to travel 10m is just
t = 10/v<sub>y</sub>
v<sub>x</sub> = 10.6 cos 32.5
v<sub>y</sub> = 10.6 sin 32.5
Now that you have v<sub>y</sub>, the time to travel 10m is just
t = 10/v<sub>y</sub>
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