Asked by Lee
                The equation  of simulated photosynthesis is represented by 
6CO2(g) + 6H2O(g)-> C6H12O6(s) + 6O2(g)
At 31 degree Celcius, the following equilibrium concentration were found.
[H2O] = 7.91X10^-2M
[CO2] = 9.30X10^-1M
[O2] = 2.40X10^-3M
My question is how to determine the initial mass of CO2 involved in the above reaction?
As I only know how to find the initial concentration of CO2
            
        6CO2(g) + 6H2O(g)-> C6H12O6(s) + 6O2(g)
At 31 degree Celcius, the following equilibrium concentration were found.
[H2O] = 7.91X10^-2M
[CO2] = 9.30X10^-1M
[O2] = 2.40X10^-3M
My question is how to determine the initial mass of CO2 involved in the above reaction?
As I only know how to find the initial concentration of CO2
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