Question

Calculate how much a 1.1 m slab of lead will expand if heated from -68 °C to 26 °C. The coefficient of thermal expansion for lead is 29×10^-6 1/(deg(C)). Express your answer in m, cm, & in. 1 in = 2.54 cm.

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Answer 1

L = (26-(-68))oC * 29*10^-6m/oC =0.002726 m. = 0.2726 cm. = 0.1073 in .