Asked by manoj kumar
a wooden slab starting from rest slide down a 10m long inclined plane with acceleration of 5m per sec what would be the speed ay the bottom of the inclined plane
Answers
Answered by
Henry
V^2 = Vo^2 + 2a*d
V^2 = 0 + 10*10 = 100
V = 10 m/s.
V^2 = 0 + 10*10 = 100
V = 10 m/s.