Asked by ezana

a concrete slab of mass 400 kg accelerates down a concrete slope inclined at 35 degrees. the coefficient of kinetic friction between the slab and slope is 0.60. determine the acceleration of the block
Answered by Damon
normal force = 400 g cos 35
friction force up slope = .6 (400 g) cos 35

weight component down slope = 400 g sin 35

400 a = 400 g sin 35 - .6 (400 g cos 35)

a = g (sin 35 - .6 cos 35) = .082 g
Answered by Anonymous
the momentum after the collision
Answered by Bgagag
400kg
Answered by fanos
I do not get it ! Would you say it works again?
Answered by Biniam
Where is full answer?
Answered by Meskerem
0967700481
Answered by Mulualem kibret
Really it's not clear
Answered by Abeno
What is this thing
Answered by Hermela
I don't understand clearly
Answered by Kedir
Mohammed