Question
A concrete slab of mass 400kg accelerates down a concrete slope in clined at35°. The
Answers
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coefficient of friction between the slab and the slope is 0.3.
What is the acceleration of the slab?
The acceleration of the slab can be calculated using the equation:
a = gsinθ - μmgcosθ
Where g is the acceleration due to gravity (9.81 m/s2), θ is the angle of the slope (35°), μ is the coefficient of friction (0.3) and m is the mass of the slab (400 kg).
Plugging in the values, we get:
a = 9.81sin35° - 0.3(400)(9.81)cos35°
a = 4.45 m/s2
What is the acceleration of the slab?
The acceleration of the slab can be calculated using the equation:
a = gsinθ - μmgcosθ
Where g is the acceleration due to gravity (9.81 m/s2), θ is the angle of the slope (35°), μ is the coefficient of friction (0.3) and m is the mass of the slab (400 kg).
Plugging in the values, we get:
a = 9.81sin35° - 0.3(400)(9.81)cos35°
a = 4.45 m/s2