Hello,

Question

I just want to make sure I'm doing this correctly:
Solve the following systems of equations algebraically.
y=x^2-1
2x-y+2=0

My work:
-x^2+2x+3=0
Divide everything by -1
x^2-2x-3=0
(x-3)(x+1)=0
x=3, x=-1

Thank you!! :)

Answer 1

check yurs
if x = -1
y = x^2 -1 = 1-1 = 0
2x - y +2 = 2(-1) - 0 + 2 = 0
yes, that checks
if x = 3
y = x^2 - 1 = 8
2(3) -8 +2 = 6 -8+2 = 0
yes that checks