Asked by Rachel
Three vectors are shown in the figure. Their magnitudes are given in arbitrary units. Determine the sum of the three vectors. Give the resultant in terms of (a) magnitude and (b) the angle within the positive x axis.
Answers
Answered by
bobpursley
no figure.
Answered by
Rachel
It wont let me insert the figure into the text box.
Answered by
Rachel
A is in quadrant one with a length of 44.0 and an angle of 28.
B is in quadrant two with a length of 26.5 and an angle of 56.
C is on the y axis facing down with a length of 31.0
B is in quadrant two with a length of 26.5 and an angle of 56.
C is on the y axis facing down with a length of 31.0
Answered by
bobpursley
changing each vector to x,y components:
I assume each angle is measured from the x axis, if not, you did not specify, you have to modify this:
A=44cos28 xbar + 44sin28 ybar
B=26.5cos(180-56)+26.5sin(180-56)ybar
C= 0 xbar-31 ybar.
Sum xbars= sum of those above; sum ybars= sum of those ybars above.
Resultant= sqrt(sumxbar^2 + sumybar^2)
angle= arctan(sumybar/sumxbar).
In vectors, in the future, please note how the angles are measured. It is very standard to measure the angles from y axis (or OOO N), clockwise.
I assume each angle is measured from the x axis, if not, you did not specify, you have to modify this:
A=44cos28 xbar + 44sin28 ybar
B=26.5cos(180-56)+26.5sin(180-56)ybar
C= 0 xbar-31 ybar.
Sum xbars= sum of those above; sum ybars= sum of those ybars above.
Resultant= sqrt(sumxbar^2 + sumybar^2)
angle= arctan(sumybar/sumxbar).
In vectors, in the future, please note how the angles are measured. It is very standard to measure the angles from y axis (or OOO N), clockwise.
Answered by
Anonymous
Three vectors are shown in the figure. Their magnitudes are given in arbitrary units. Determine the sum of the three vectors. Give the resultant in terms of (a) magnitude and (b) the angle within the positive x axis.