Vectors u=2i+9j+0k and v=13i+18j+0k. What is the value of |u×v|?

Answer 1

This is the magnitude of the cross product.
The cross product is obtained by evaluating the determinant
p
i j k
2 9 0
13 18 0

which is
p=0i+0j+(2*18-9*13)k
=-81k

The magnitude is therefore 81.

Answer 2

thanks sir!!!!

Answer 3

You're welcome!