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You are given vectors A⃗ = 4.8 i^− 6.7 j^ and B⃗ = - 3.4 i^+ 7.5 j^. A third vector C⃗ lies in the xy-plane. Vector C⃗ is perpendicular to vector A⃗ and the scalar product of C⃗ with B⃗ is 17.0.
11 years ago

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Answered by Anonymous
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8 years ago
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You are given vectors A⃗ = 4.8 i^− 6.7 j^ and B⃗ = - 3.4 i^+ 7.5 j^. A third vector C⃗ lies in the xy-plane. Vector C⃗ is perpendicular to vector A⃗ and the scalar product of C⃗ with B⃗ is 17.0.

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