Asked by joy
                Three vectors are shown in the figure below, but they are not drawn to scale. The sum of the three vectors is R = F1 + F2 + F3. If Ry = 0 and F2 = 0.2F3, find Rx in terms of F1. the Answer Keyis 0.327.can somebody show me how to get to the answer key. I try my best to describe the figure. the figure looks like an x with an exra line draw from the center of the x downward in other word like an upside down star. F1 is that line and on the left of that line is 30degree. F2 point on the north-west side and F3 point on the north-east side. Please help.I'm stuck.
  
            
            
        Answers
                    Answered by
            bobpursley
            
    I need the figure.
    
                    Answered by
            joy
            
    do you know anyway for me to show you the figure on this site  bobpursley?I had try copy and pasted but not show up and I can't paste any link on this site either.
    
                    Answered by
            joy
            
    bobpursley I just send you an email. check and see did you receive it yet 
    
                    Answered by
            bobpursley
            
    so Ry is zero, which means cos30*F1=-F3
and F2 = 0.2F3, so
Rx=???F3 is the question
Rx=sin30*F1 from the figure.
Rx=.5F1-F2=.3(-F3/cos30)-.2F3 and you have it.
check my thinking.
    
and F2 = 0.2F3, so
Rx=???F3 is the question
Rx=sin30*F1 from the figure.
Rx=.5F1-F2=.3(-F3/cos30)-.2F3 and you have it.
check my thinking.
                    Answered by
            joy
            
    I don't get it what is the value forF1? can you show step by step with number? 
    
                    Answered by
            bobpursley
            
    Opps, I solve it for Rx in terms of F3, you want it in terms of F1
Rx=F1*sin30-F2
= .5F1-.2F2
but F2=.2F3=.2(-F1*cos30)
Rx=.5F1-.2* cos30 F1
=F1(.5-.2*.866)=.327F1
  
    
Rx=F1*sin30-F2
= .5F1-.2F2
but F2=.2F3=.2(-F1*cos30)
Rx=.5F1-.2* cos30 F1
=F1(.5-.2*.866)=.327F1
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