Given
a=<-1,-4,2>
b=<3,2,-2>
c=<2,-3,1>
bxc=
i j k
3 2-2
2-3 1
=<-4,-7,-13>
so
a.(bxc)
=<-1,-4,2>.<-4,-7,-13>
=4+28-26
=6
Given three vectors
a⃗ =−i⃗ −4j⃗ +2k⃗
,
b⃗ =3i⃗ +2j⃗ −2k⃗
,
c⃗ =2i⃗ −3j⃗ +k⃗
, calculate
a⃗ ⋅(b⃗ ×c⃗ )
1 answer