Asked by Alina
A projectile is launched at an angle of 20.0° above the horizontal. What is its initial speed if it hits a target that is located a horizontal distance of 175 m from the launch point and 10.5 m above the launch level?
Answers
Answered by
Damon
S is initial speed
u = S cos 20 forever
so
175 = S cos 20 * t
so t = 175 / (S cos 20)
then the height
10.5 = 0 + S sin 20 * t - 4.9 t^2
10.5 = 175 tan 20 - 4.9 [175^2 / (S^2 cos^2 20)] solve for S
u = S cos 20 forever
so
175 = S cos 20 * t
so t = 175 / (S cos 20)
then the height
10.5 = 0 + S sin 20 * t - 4.9 t^2
10.5 = 175 tan 20 - 4.9 [175^2 / (S^2 cos^2 20)] solve for S
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