Question

A slab of a thermal insulator is 100 cm² in cross section and 2 cm thick. Its thermal conductivity is 2.4 x 10-4 cal/s.cm.°C. If the temperature difference between the opposite faces is 100 degrees Celsius, how much heat flows through the slab in one day?

Answer 1

heat flow=conductivity*area/distance*(temp difference)*timeinSeconds
= 2.4e-4(100/2)(100)*(3600*24) calories