Asked by paul
a slab of ice floats on a freshwater lake what is the minimum volume must the slab have for a 45kg women to be able to stand on it without getting her feet wet?
Answers
Answered by
drwls
Weight of ice slab + weight of woman = buoyancy force
(ice density)*V*g + Mg = (water density)*V*g
[(Water density)-(Ice density)]*V = M = 45 kg
V = 45 kg/[(Water density)-(Ice density)]
= 45kg/(1000 - 917)kg/m^3 = 0.54 m^3
(ice density)*V*g + Mg = (water density)*V*g
[(Water density)-(Ice density)]*V = M = 45 kg
V = 45 kg/[(Water density)-(Ice density)]
= 45kg/(1000 - 917)kg/m^3 = 0.54 m^3
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