Asked by Alli
rules of logarithms: can someone please explain how to do these problems?
I understand the rules I just don't understand how they apply
1. e^(3lnx)
2. e^(1+2lnx)
thanks!
I understand the rules I just don't understand how they apply
1. e^(3lnx)
2. e^(1+2lnx)
thanks!
Answers
Answered by
Reiny
the first is a direct result of the "rule" that I showed you in your post from last night. Did you look at it?
http://www.jiskha.com/display.cgi?id=1233373241
for the second....
e^(1+2lnx)
= (e^1)(e^2lnx) , to multiply powers with the same base, we add the exponents
= (e^1)(e^lnx^2)
= e(x^2)
http://www.jiskha.com/display.cgi?id=1233373241
for the second....
e^(1+2lnx)
= (e^1)(e^2lnx) , to multiply powers with the same base, we add the exponents
= (e^1)(e^lnx^2)
= e(x^2)
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